Is the following function a heart, loop or rose?
Is the function symmetric to the x-axis, y-axis, or the origin? r=1+2cos(x)
a) Heart, symmetric to the x-axis
b) Loop, symmetric to the y-axis
c) Loop, symmetric to x-axis
d) Heart, symmetric to the y-axis

x(t)= t^3 + 4t^2 , y(t)= t^4 - t^3
Find the velocity vector when t=1
a) <11,3>
b) <3,11>
c) <3,9>
d) <11,1>

Graph the following polar equation on the board:
r=2sin3x

How many petals does the following rose function have? r=6cos(4x)
a) 6 petals
b) 8 petals
c) 4 petals
d) 2 petals

Write down the formula for the magnitude of a velocity vector on the board.

x'(t)= sin(t^3) , y'(t)= cos(t^2)
Find the acceleration vector at t=2 (calculator active)
a) <-1.543,3.027>
b) <3.027,-1.543>
c) <-1.746,3.027>
d) <3.114,-1.746>

2 Part Question:
Is the following function a heart, loop or rose?
Is the function symmetric to the x-axis, y-axis, or the origin?
r=2sin(3x)

x(t)= t^2 + 3t ; y(t)= t^3 - 3t^2
Find the magnitude of the velocity vector when t=1
a) (34)^(1/2)
b) 6
c) (32)^(1/2)
d) (38)^(1/2)

Graph the following polar equation on the board:
r=1 + 2cosx